0=-0.5d^2+2d+5

Solution for 0=-0.5d^2+2d+5 equation:

0=-0.5d^2+2d+5

We move all terms to the left:

0-(-0.5d^2+2d+5)=0

We add all the numbers together, and all the variables

-(-0.5d^2+2d+5)=0

We get rid of parentheses

0.5d^2-2d-5=0

a = 0.5; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·0.5·(-5)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{14}}{2*0.5}=\frac{2-\sqrt{14}}{1}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{14}}{2*0.5}=\frac{2+\sqrt{14}}{1}
$